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What is the wavelength λ of the photon that has been released in part b?

Delta E=2.05×10−18 {\rm J}

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Final answer:

The energy difference between states can be used to calculate the wavelength of the photon produced. By using the equation λ = c / frequency, and substituting in the known values for c and h, we can find the wavelength.

Step-by-step explanation:

The energy difference between states is given by AE = 2μB B.

Using this equation, we can find the wavelength of the light produced, which is given by the equation λ = c/frequency = c/(AE/h).

Given that the energy difference is 2.05x10-18 J, we can substitute these values to find the wavelength of the photon:

λ = c/(2.05x10-18 J / (h))

Plugging in the known values for c (speed of light) as 3.00x108 m/s and h (Planck's constant) as 3.99x10-13 kJ.s.mol-1, we can calculate the wavelength of the photon.

User Kim Oliveros
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