Question

Can someone help. plsWhich is the equation of the line through the points (-3,4) and (5,4)?

Answer 1

First, you can find the slope of the line using the equation

`m=(y_2-y_1)/(x_2-x_1)`

If you take (-3,4) as P1 and (5,4) as P2 you have

`m=(y_2-y_1)/(x_2-x_1)=(4-4)/(5-(-3))=(0)/(5+3)=(0)/(8)=0`

Then, to obtain the equation of the line you can use the equation point slope, that is

`y-y_1=m(x_{}-x_1)`

And so you get

`\begin{gathered} y-y_1=m(x_{}-x_1) \\ y-4=0(x-(-3)) \\ y-4=0 \\ y=4 \end{gathered}`

Therefore, the equation of the line that passes through the points (-3,4) and (5,4) is y=4.