Question

What is the volume of 0.58 moles
of H2 gas at STP?

Answer 1

volume = 0.013 m³

Step-by-step explanation:

The question asks us to calculate the volume of 0.58 moles of H₂ gas at STP.

To do this, we must use the ideal gas equation:

`\boxed{pV = nRT}`,

where:

• p = pressure in Pa

• V = volume in m³

• n = number of moles

• R = molar gas constant (8.31 Jkg⁻¹K⁻¹)

• T = temperature in K

From the question, we know that the number of moles of H₂ is 0.58. Therefore, n = 0.58. We also know that the volume is asked for when the gas is at STP, therefore: T = 273 K, and p = 101.3 × 10³ Pa.

Using this data and the formula above, we can calculate the volume of the gas:

pV = nRT

⇒ 101.3 × 10³ × V = 0.58 × 8.31 × 273

⇒ V =
`(0.58 * 8.31 * 273)/(101.3 * 10^3)`

⇒ V = 0.013 m³

Therefore, the volume of the gas is 0.013 m³.