Question

A ball is Projected horizontally from a height of 20cm above d ground with an initial velocity OR 0.4ms! Calculated hori- Zontal distance moved by the ball before hitting! d ground. [9 = loms ~2]~​

Answer 1

The horizontal distance moved by the ball before hitting the ground is 0.08 meters.

Step-by-step explanation:

To solve this problem, we can use the equations of projectile motion. Since the ball is projected horizontally, its initial vertical velocity is 0 m/s. The ball will fall vertically due to gravity, and we can calculate the time it takes to hit the ground using the equation:

time =
`√(2 * height) / g)`

where g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we get:

time =
`√(2 * 0.2) / 9.8)` = 0.2 s.

Next, we can calculate the horizontal distance using the equation:

distance = velocity * time

Since the initial velocity in the horizontal direction is 0.4 m/s and the time is 0.2 s, we get:

distance = 0.4 * 0.2 = 0.08 m.

Therefore, the horizontal distance moved by the ball before hitting the ground is 0.08 meters.

Answer 2

you can calculate the horizontal distance i.e s by applying the motion formula.

Step-by-step explanation:

First .you should calculate the time period of the ball

h=ut + 1/2 at²

then,v²=u² +2as

a=v-u÷t