Answer: By SSS, ΔSUR ≅ ΔTVR.
Explanation:
This might be a longer method, but still here you go.
Given, ΔSTU ≅ ΔTSV
By CPCT, we have the following.
∠TUS / ∠RUS = ∠SVT / ∠RVT ---- 1
SU = TV ---- 2
SV = TU ---- 3
∠STU / ∠STR = ∠TSV / ∠TSR
Now, in the triangle TRS,
TR = SR ( ∠TSR = ∠STR) ---- 4
SV= TU
SV - SR = TU - TR (SR= TR)
UR = VR ---- 5
Now, we can use SSS in the triangles ΔSUR and ΔTVR
SU = TV (2)
SR = TR (4)
UR = VR (5)
Therefore, by SSS, ΔSUR ≅ ΔTVR.
Cheers