Question

A collection of jewelry includes two rings, one 10 years old and the other 31 years old. In how many years will the older ring be twice as old as the newer ring? i dont now what to do pls help me

Answer 1

ng "x". If the older ring is 31 years old, then the difference in age between the two rings is 31 - 10 = 21 years.

We know that the older ring will be twice as old as the newer ring when the difference in age between them is x.
So, we can set up an equation:

31 - 10 = x

31 - x = 10

Now we know that in x years, the older ring will be twice as old as the newer ring.

Therefore, in x years the older ring will be 31 years old and the newer ring will be 10+x years old.

x = 21 years

So, in 21 years the older ring will be twice as old as the newer ring.

Answer 2

a collection to two rings Yes that is the right answer! good job