To find the number of revolutions the tire makes during this motion, we need to know the distance traveled by the car and divide that by the circumference of the tire.
The speed, v, of a car that accelerates uniformly from rest is given by v = at, where a is the acceleration and t is the time. In this case, the final speed is 17.3 m/s and the time is 6 s, so the acceleration is 17.3 m/s / 6 s = 2.88 m/s^2.
The distance, s, traveled by the car during this motion is given by s = 1/2at^2, where a is the acceleration and t is the time. In this case, the acceleration is 2.88 m/s^2 and the time is 6 s, so the distance traveled is 0.5 * 2.88 m/s^2 * 6 s^2 = 41.76 m.
Now we need to find the circumference of the tire, which is given by the diameter multiplied by pi. In this case, the diameter is 66.5 cm = 0.665 m, so the circumference is 0.665 m * pi = 2.09 m.
Finally, we divide the distance traveled by the car by the circumference of the tire to get the number of revolutions the tire makes:
41.76 m / 2.09 m = 19.998 rev
So the number of revolutions the tire makes during this motion is approximately 20 rev (Rounding the result to two decimal places)