Question

The length of one diagonal of a rhombus is 6 times the length of the other diagonal. Write an expression that represents the perimeter of the rhombus, where d represents the shorter diagonal. ​

Answer 1

14d

Explanation:

First the short diagonal is d, so we can mark it as d:

d

Second we have 6 times that, so 6d:

d+6d

Then we multiply it by two since a rhombus has 4 sides:

2d+12d

Then we simplify:

14d

Voila!

Answer 2

A rhombus is a four-sided shape with all sides equal in length, and opposite angles equal. The diagonals of a rhombus bisect each other at right angles and they are equal in length.

In this case, the length of one diagonal of the rhombus is 6 times the length of the other diagonal. Let's call the length of the shorter diagonal "d", and the length of the longer diagonal "6d".

To find the perimeter of the rhombus, we can add up the lengths of all four sides. Since all sides of a rhombus are equal, we can find the perimeter by multiplying the length of one side by 4.

To find the length of one side, we can use the Pythagorean theorem to find the length of the side in terms of d, the shorter diagonal.

We know that d^2 + (3d)^2 = s^2, where s is the length of one side.

After simplifying, we get: d^2 + 9d^2 = s^2

s = √10d^2

so the perimeter is 4s = 4 √10d^2

Therefore, the perimeter of the rhombus can be represented by the expression 4* √10d^2 where d represents the length of the shorter diagonal.