Question

Pls help

If the eggs in a basket are removed six at a time, five eggs will remain. If the eggs are removed five at a time, only four will remain. If the eggs are removed four, three, or two at a time, then three, two, and one egg will remain, respectively. But if the eggs are taken out seven at a time, no eggs will be left over. What is the least number of eggs that could be in the basket?

Answer 1

119 eggs

Explanation:

To start off, we know that this number has to be of some multiple of 7. Because if the eggs are taken out 7 at a time, and no eggs are left over, then the total number of eggs can be divisible by 7. Because there is however a multiple if you take out the eggs 2-6 times, there are eggs left over. The smallest multiple of 7 we can test is simply 7. To check, we can start with dividing 7 by 6 and getting a remainder of 1 instead of 5. So we know that 7x1 doesn't work.

The next smallest multiple of 7 that isn't multiplied from 2-6 is 7x7 to get 49. from here we can check that 49/6 = 8 r1 (r meaning remainder). So we know that 7x7 can't work. From here, the next smallest number would be 7x11.

7x11 = 77. 77/6 is 12 r5. This so far looks good. Now we can try 5. 77/5 = 15 r2. This doesn't work, so we try the next largest number which is 7x13 which is 91.

91/6 = 15 r1 which doesn't work. Next we try 7x17 which is 119. 119/6 is 19 r5 (looks good), 119/5 = 23 r4 (looks good), 119/4 is 29 r3, 119/3 is 39 r2, and 119/2 is 59 r1! Which means our answer is that the least number of eggs in the basket is 119.