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Identify a quadratic function that fits the points (−3, −7),(0, −4), and (2, −12).

1 Answer

2 votes

Answer:

f(x) = -x² -2x -4

Explanation:

You want a quadratic function that fits the points (-3, -7), (0, -4), and (2, -12).

Equations

A straightforward way to find the quadratic function is to write equations for the values of the coefficients.

f(x) = ax² +bx +c

f(-3) = -7 = a(-3)² +b(-3) +c = 9a -3b +c

f(0) = -4 = a(0)² +b(0) +c = c . . . . . . c = -4

f(2) = -12 = a(2)² +b(2) +c = 4a +2b +c

Solution

These can be solved by a variety of methods. The second attachment shows one of them. It tells us (a, b, c) = (-1, -2, -4).

Since we know c = -4, we can write this as 2 equations in 'a' and 'b'.

9a -3b = -3

4a +2b = -8

Removing common factors gives the standard-form equations ...

3a -b = -1

2a +b = -4

Adding these, we have ...

5a = -5

a = -1

So, ...

2(-1) +b = -4

b = -2

The quadratic function is ...

f(x) = -x² -2x -4

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Additional comment

The quadratic regression function of a calculator or spreadsheet can also find the equation for you. This is also shown in the second attachment.

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Identify a quadratic function that fits the points (−3, −7),(0, −4), and (2, −12).-example-1
Identify a quadratic function that fits the points (−3, −7),(0, −4), and (2, −12).-example-2