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Comment calcule t'on (4x+5)²−25=0
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Comment calcule t'on (4x+5)²−25=0

User Nasaralla
by
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1 Answer

4 votes

Answer:

x = 0 and

x = -(5/2)

Explanation:

(4x+5)²−25=0
(16x^2+40x + 25) - 25 = 0 [expand the square]

16x^2+40x = 0

8x(2x+5)=0

the roots are 8x=0 and 2x+5 = 0

x = 0 and x = -(5/2)

User Munda
by
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