Question

How likely is it for Bryson to choose a number greater than four?

Answer 1

Likely

Explanation:

Let's list out all the numbers 1 to 12 first:

1 2 3 4 5 6 7 8 9 10 11 12

Nice! Now let's only keep the numbers that are greater than 4, since the other numbers don't satisfy the condition of "greater than 4"

5 6 7 8 9 10 11 12

There are 8 options that Bryson could choose out of all the 12 options. We can express that as 8 over 12:

`(8)/(12)`

Then, we simplify this by dividing both the numerator and denominator by 4, and we get:

`(2)/(3)`

Therefore, it is a 2/3 chance that Bryson will choose a number greater than 4, and we would say that 2/3 chance is likely, but not certain.

Answer 2

1. 59% chance of drawing an odd card. "As likely as not."

2. A 66.67% chance of drawing a number greater than 4. Likely

Explanation:

We will assume that all card draws are random, as promised.

The likihood of drawing an odd number is determined by counting how many numbers in the cards labelled 1 - 12 are odd. There are 6 odd and 6 even cards. Bryson's change of picking an odd card, randomly, is 6/12 (6 times out of 12 tries). That's a 50% chance. I don't see the options for answers, but "As likely as not" would be correct. The chance for even is also 6/12, or 50%

To determine the likihood of picking a number great than 4, count the values greater than 4 (5,6,7,8,9,10,11,12) There are 8 values greater than 4. Bryson has an 8/12 chance of picking a number greater than 4. That would mean a 66.666% chjance, which I would consider "likely."