Question

12 This question is about a parachutist.

(a) A parachutist leaves a helicopter that is hovering above the ground.
The parachutist is initially at rest and falls vertically downwards.
Calculate the speed of the parachutist after they have fallen through a distance
of 1300m.
Ignore the effect of air resistance.

Answer 1

159.6 m/s²

Step-by-step explanation:

The third equation of motion is

v² = u² + 2gs

where v = final velocity

u = initial velocity or 0 ( body is initially at rest)

g = acceleration due to gravity = 9.8 m/s²

s = 1300 m

v² = 2gs

v² = 2600 x 9.8

v = √(2600 x 9.8

v is approximately 159.6 m/s^2

WHICH IS A LOT.