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How would you solve questions 25a+b?

How would you solve questions 25a+b?-example-1

1 Answer

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Answer:

(a) See attachment.

(b) 12:23

Explanation:

Part (a)

A bearing is the angle (in degrees) measured clockwise from north.

To mark the position of J on the given map:

  • Measure an angle of 36° clockwise from K and draw a line.
  • Measure an angle of 284° clockwise from L and draw a line.
  • The location of J is the point of intersection of the two lines.

(See attachment).

Part (b)

Given:

  • Distance between K and L = 9600 m
  • Speed Kendra walks from K to L = 4.5 km/h

Convert 9600 meters into kilometers by dividing by 1000:

⇒ 9600 m = 9600 ÷ 1000 = 9.6 km


\boxed{\sf Speed=(Distance)/(Time)}

Therefore:


\sf Time=(Distance)/(Speed)

Substitute the given distance and speed into the formula to calculate the time it took Kendra to walk from K to L:


\implies \sf Time=(9.6\;km)/(4.5\;km/h)=2.133333...\;hours

Convert 2.133333.. into a mixed number:


\implies \sf 2.133333...=2(2)/(15)\;hours

To find the number of minutes in 2/15ths of an hour, multiply 2/15 by 60:


\implies \sf (2)/(15) * 60=(120)/(15)=8\;minutes

Therefore, it took Kendra 2 hours and 8 minutes to walk from K to L.

If Kendra left at 10:15:


\implies \sf 10:15 + 2\;hours = 12:15


\implies \sf 12:15 + 8\;minutes=12:23

Therefore, Kendra arrived at L at 12:23.

How would you solve questions 25a+b?-example-1
User Jaspero
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