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Glucose (C6H12O6) is burned in the human body for energy. Carbon dioxide and water are produced as waste products. How many moles of oxygen are needed to combust 3.12 moles of glucose?​

User Ryna
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18.72 moles of oxygen are needed to combust 3.12 moles of glucose.

Glucose is a type of sugar that can be represented by the chemical formula C6H12O6.

When glucose is burned in the human body, it combines with oxygen to form carbon dioxide (CO2) and water (H2O) as waste products.

The balanced equation for the combustion of glucose is:

C6H12O6 + 6O2 -> 6CO2 + 6H2O

From the equation, we can see that for every 1 mole of glucose, 6 moles of oxygen are needed.

To calculate the number of moles of oxygen needed to combust 3.12 moles of glucose, we can use this relationship;-

3.12 moles of glucose * 6 moles of O2/1 mole of glucose = 18.72 moles of O2

So, 18.72 moles of oxygen are needed to combust 3.12 moles of glucose.

User Antiarchitect
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