Answer:
d = 4 and a₁ = 12
Explanation:
the nth term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
given a₆ = 32 and a₁₀ = 48 , then
a₁ + 5d = 32 → (1)
a₁ + 9d = 48 → (2)
subtract (1) from (2) term by term to eliminate a₁
0 + 4d = 16
4d = 16 ( divide both sides by 4 )
d = 4
substitute d = 4 into (1) and solve for a₁
a₁ + 5(4) = 32
a₁ + 20 = 32 ( subtract 20 from both sides )
a₁ = 12