Answer:
89.51g of KClO4 is 0.03566 Liters (4 sig figs)
Step-by-step explanation:
o calculate the liters in 89.51 grams of KClO4, we need to use the density of the substance. The density of KClO4 is 2.52 g/mL. To convert from grams to milliliters, we can use the formula:
Volume (mL) = mass (g) / density (g/mL)
Now we can plug in the given values:
Volume (mL) = 89.51 g / 2.52 g/mL = 35.66 mL
To convert mL to Liters we divide by 1000, so the volume of 89.51g of KClO4 is 0.03566 Liters (4 sig figs)