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Calculate the liters in 89.51 grams of KCl4O

Answer in four sig figs

1 Answer

3 votes

Answer:

89.51g of KClO4 is 0.03566 Liters (4 sig figs)

Step-by-step explanation:

o calculate the liters in 89.51 grams of KClO4, we need to use the density of the substance. The density of KClO4 is 2.52 g/mL. To convert from grams to milliliters, we can use the formula:

Volume (mL) = mass (g) / density (g/mL)

Now we can plug in the given values:

Volume (mL) = 89.51 g / 2.52 g/mL = 35.66 mL

To convert mL to Liters we divide by 1000, so the volume of 89.51g of KClO4 is 0.03566 Liters (4 sig figs)

User Neel Salpe
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