CALCULATE THE [H3O+] FOR A URINE SAMPLE, WHICH HAS A PH OF 7.5

asked Sep 18, 2024 170k views

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use the formula [H3O+] = 10^-pH

plug in the pH [H3O+] = 10^-7.5

so [H3O+] = 3.162*10^-8 M

Tabrej Khan answered Sep 23, 2024

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