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if the line passing through the points (a,2) and (4,9) is parallel to the line passing through the points (3,11) and (a+1,3) what is the value of a?​

1 Answer

4 votes

Answer:

a = 18

Explanation:

The slopes of parallel lines are equal as


m_(2)=m_(1)

We know that the slope formula is


(y_(2)-y_(1) )/(x_(2)-x_(1) ), where y2, x2, y1, and y2 are any two points.

Thus, since the slopes are equal, we can use the slope formula to find the slopes of both lines and set them equal to each other to find a:


(9-2)/(4-a)=(3-11)/((a+1)-3) \\\\(7)/(4-a)=(-8)/(a-2) \\\\7(a-2)=-8(4-a)\\7a-14=-32+8a\\7a=-18+8a\\-a=-18\\a=18

If we plug in a for any of the two lines, we see that the slope is -1/2

Line 1 w/ (a, 2) & (4, 9):


(9-2)/(4-18)\\ (7)/(-14)\\ (-1)/(2)

Line 2 w/ (3, 11) & (a+1, 3):


(3-11)/(18+1-3)\\ (-8)/(19-3)\\ (-8)/(16)\\ (-1)/(2)

User Kevin Peno
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