Question

Given the following point on the unit circle, find the angle, to the nearest tenth of a

degree (if necessary), of the terminal side through that point, 0° 0 < 360°.
P =
3
4
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47)

Answer 1

Answer:
`303^(\circ)`

Explanation:

The point
`P` lies in the fourth quadrant, so the angle is given by
`360^(\circ)-\alpha`, where
`\alpha` is the reference angle.

The reference angle is given by
`\arctan \left(((√(7))/(4))/((√(3))/(4)) \right)=\arctan \left(\sqrt{(7)/(3)} \right)`.

This means
`\theta=360^(\circ)-\arctan \left(\sqrt{(7)/(3)}} \right) \approx 303^(\circ)`.