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Given the following point on the unit circle, find the angle, to the nearest tenth of a

degree (if necessary), of the terminal side through that point, 0° ≤ 0 < 360°.
P=
√15
5
√10
5

Given the following point on the unit circle, find the angle, to the nearest tenth-example-1

1 Answer

2 votes

Answer:

60°

Explanation:

To find the angle of the terminal side through a point P on the unit circle, we can use the coordinates of the point. The angle is given by the inverse tangent (atan) of the y-coordinate divided by the x-coordinate.

The point P is given as (√15/5, √10/5)

Using the arctan function we have:

theta = arctan(√10/5/√15/5) = arctan(√2/√3)=atan(√2/√3) = pi/3

The angle theta is in radians, to convert it to degree we multiply it by 180/pi

Theta = (pi/3) * (180/pi) = 60. Therefore, the angle of the terminal side through the point P is 60°.

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