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Given v = 60sinθ, what is the rms voltage?Question 19 options:A. 60B. 84.84C. 120D. 42.42

User Chrystolin
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1 Answer

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9 votes

The RMS voltage (V-RMS) of a sinusoidal waveform is determined by multiplying the peak voltage value by 0.7071, which is the same as one divided by the square root of two ( 1/√2 ).


V_(RMS)=V_(PK)*\frac{1}{\sqrt[]{2}}=V_(PK)*0.7071

The question provides that:


V=60\sin \theta

The peak voltage is at


\theta=90\degree

Therefore, the peak voltage is given to be:


V_(PK)=60\sin (90)=60

Hence, the RMS voltage is gotten to be:


V_{\text{RMS}}=60*0.7071=42.42

The correct option is OPTION D.

User Oles Savluk
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