Question

Two cycles 72miles apart start riding towards each other at the same time one cyclist 3 times as fast as the other if they meet 3 hours later what is the speed (in mi/h) of the fastest cyclist

Answer 1

The faster cyclist is traveling at 72 miles per hour.

Explanation:

We know that the two cyclists are 72 miles apart and meet 3 hours later. We also know that the faster cyclist is 3 times as fast as the slower cyclist.

Let's call the speed of the slower cyclist x miles per hour.

If the faster cyclist is 3 times as fast as the slower cyclist, then their speed is 3x miles per hour.

We can use the formula: distance = speed x time

The distance covered by the slower cyclist is:

x * 3 = 72 miles

The distance covered by the faster cyclist is:

3x * 3 = 72 miles

We can use the formula: distance = speed x time again

x * 3 = 72

x = 24 miles/h

So the slower cyclist is traveling at 24 miles per hour.

To find the speed of the faster cyclist, we know that the faster cyclist is 3 times as fast as the slower cyclist.

The speed of the faster cyclist is:

3 * 24 = 72 miles/h