Question

A 7,500-W engine is used to lift an I-beam with a mass of 1,000 kg to a height of 150 m. How much work must be done to lift this mass at a constant speed? How long will it take?

Use these formulas: W = F x d F = m x 9.8 m/s² t = W/P

Answer 1

Step-by-step explanation:

Power = 7500 watts

mass = 1000kg

height/distance= 150m

work= ?

time = ?

second equation for motion

2nd law of newton

F = ma

for free fall motion a = g= 9.8

force = 9800Newton

now for work done

w = force into displacement

workdone = 1470000 Joules

now finally by power formula

p = workdone upon time

time = workdone upon power

time = 196 second

I hope this would help you!

Answer 2

Step-by-step explanation:

The work that must be done to lift the mass is W = F x d = 1000 kg x 9.8 m/s2 x 150 m = 1,470,000 Joules (1.47 x 106 J).

The time it will take to lift the mass at a constant speed is t = W/P = 1.47 x 106 J/7500 W = 196 seconds (3 minutes 16 seconds).