Question

Calculate the number of moles of each of the ions in the following solution:36.5 mL of 0.595 M (NH4)2CO3NH4+: molCO32-: mol

Answer 1

The first step is to determine how many moles of each ion are there in one mole of (NH4)2CO3.

In one mole of (NH4)2CO3, there are 2 moles of NH4 + and 1 mole of CO3 2-.

Find the number of moles that are present in 36.5mL of solution by multiplying this volume times the concentration of the solution. First convert the mililiters to liters (1L=1000mL):

`\begin{gathered} 36.5mL\cdot(L)/(1000mL)=0.0365L \\ 0.0365L\cdot(0.595mol)/(L)=0.0217mol(NH_4)_2CO_3 \end{gathered}`

Finally, use the amounts of moles of each ion per mole of substance (determined at the beginning) to find the amount of moles of each ion present in the given volume:

`\begin{gathered} 0.0217mol(NH_4)_2CO_3\cdot(2molNH^+_4)/(1mol(NH_4)_2CO_3)=0.0434molNH^+_4 \\ 0.0217mol(NH_4)_2CO_3\cdot\frac{1molCO^(2-)_3^{}_{}}{1mol(NH_4)_2CO_3}=0.0217molCO^(2-)_3 \end{gathered}`