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Zoe is designing an exhibit of her paintings and has at most 315 square feet of wall

space on which to display them. Her paintings take up 22 square feet each. She must
also have a sign from the gallery posted on her wall. The sign is 9 square feet. Which
inequality can be used to solve for how many x paintings can be displayed?
O22x +9 315
O22x +92 315
9x+22315
O22z+9 315

Zoe is designing an exhibit of her paintings and has at most 315 square feet of wall-example-1

1 Answer

3 votes

Answer:

The inequality that can be used to solve for how many x paintings can be displayed is 22x + 9 <= 315

Explanation:

This inequality states that the total square footage of the paintings and the sign must be less than or equal to 315 square feet. Each painting takes up 22 square feet, and the sign takes up 9 square feet, so the total square footage is represented by the expression 22x + 9.

The inequality states that 22x + 9 <= 315 which means for any number of paintings she displays it should be less than or equal to 315 sq.ft.

The other options:

22x + 9 315: the inequality is less than instead of less than or equal to, which means that the total cost should be less than 315 sq.ft which is not always the case.

22x + 92 315: the coefficient of x is 22 instead of 22 and the 92 is placed in a wrong position.

9x+22 315: the coefficient of x is 9 instead of 22 and the 22 is placed in a wrong position.

22z + 9 315: the variable used is z instead of x

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