Question

30 J of work are done in 15 seconds to push a bowl of fruit horizontally. What was the power delivered completing this task?

Answer 1

Step-by-step explanation:

The power delivered completing this task can be calculated using the formula Power = Work/Time. In this case, the power is equal to 30 J/15 s, which simplifies to 2 J/s. This can also be expressed as 2 Watts (W).

Answer 2

Important Formulas:

`p=(w)/(t)`

power(measured in watts) = work(measured in joules) / time(measured in seconds)

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Given:

`w=30J`

`t=15s`

`p=?`

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Finding power:

`p=(w)/(t)`

`p=(30)/(15)`

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`\fbox{p = 2 watts}`