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F(x) = x-4 / x^2 +13x + 36

User LCE
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Answer:

Explanation:

This is a quadratic function, which is a function of the form f(x) = ax^2 + bx + c, where a, b and c are constants. The function can be written in general form as f(x) = (x-4) / (x^2 +13x + 36).

To find the roots of the function (i.e. the points at which the function intersects the x-axis), we can use the quadratic formula:

x = [-b +/- sqrt(b^2 - 4ac)] / 2a

In this case, a = 1, b = 13 and c = 36.

Substituting these values into the quadratic formula, we get:

x = [-13 +/- sqrt(169 - 4(1)(36))] / 2

x = [-13 +/- sqrt(97)] / 2

x = [-13 +/- 9.8488578] / 2

x1 = -1.1744289

x2 = 11.1744289

Therefore, the roots of the function are x1 = -1.1744289 and x2 = 11.1744289.

User Egze
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