Question

Graphing Lines How would you graph 10x-3y=15

Answer 1

y=10/3x+5

(0,5), (3,15)

Explanation:

First, put the graph in slope-intercept form. We can do this by subtracting 10x from both sides.

-3y=-10x-15

Next, we divide by -3.

y=10/3x+5

If you don't know how to graph an equation with slope-intercept form,

it is in the format of y=mx+b, where m is the slope (in this case, 10/3) and b is the y-intercept (in this case 5, or (0,5)). First graph the y-intercept.

(0,5).

Then implement the slope. Here we would go up by 10 and then go right by 3. This makes our second point (3,15).

Now that we have two points (0,5) and (3,15), just construct your line.

Answer 2

Explanation:

To graph 10x-3y=15, start by rearranging the equation to the slope-intercept form of y = mx + b, where m = the slope and b = the y-intercept. 10x-3y=15 becomes 3y = 10x - 15. Solve for y by dividing both sides by 3 to get y = (10/3)x - 5.

Now that the equation is in the slope-intercept form, draw a graph on a coordinate plane. Start by plotting the y-intercept at (0, -5). Next, use the slope of 10/3 to determine the rise and run of the line. The rise is +10 and the run is +3. Starting at the y-intercept, draw a line that moves up 10 and to the right 3, and continue doing this until you reach the end of the graph. This line is the graph of 10x-3y=15.