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A 9.87 g mixture contains 1.07 grams of NaCl and8.47 grams of SiO_2, the remaining is NH_4Cl. Determine the percentage by mass of each component in the mixture. (Show calculations)

User Winter Soldier
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1 Answer

15 votes
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Step-by-step explanation

Given:

Total mass of the mixture = 9.87 g

Mass of NaCl = 1.07 g

Mass of SiO2 = 8.47 g

Mass of NH4Cl = ?

Required: Percentage by mass of each component in the mixture

Solution:

Step 1: Find the mass of NH4Cl

Mass of NH4Cl = Total mass - mass of NaCl - mass of SiO2

Mass of NH4Cl = 9.87 - 1.07 - 8.47

Mass of NH4Cl = 0.33 g

Step 2: Calculate the percentage of each component in the mixture

% of NaCl : (1.07/9.87)*100 = 10.8%

% of SiO2 : (8.47/9.87)*100 = 85.8%

% of NH4Cl : (0.33/9.87)*100 = 3.3%

Answer:

% of NaCl : (1.07/9.87)*100 = 10.8%

% of SiO2 : (8.47/9.87)*100 = 85.8%

% of NH4Cl : (0.33/9.87)*100 = 3.3%

User Toscanelli
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