Answer:
a ≠ 0
Explanation:
You want to know the restriction applicable to 2(y+a)/a(x-3).
Undefined
A rational expression is undefined when its denominator is zero. The restrictions are applied so that no denominator is zero.
Here, the expression is ...
The only denominator is 'a'. It cannot be zero.
The restriction is a ≠ 0.
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Additional comment
If we assume this is a relation in which x- and y- are the only variables, there is no restriction on the relation as written.
Perhaps you intend that (x-3) be a denominator factor. Then the relation would have the restriction x≠3. Such an expression would need to be written as ...
2(y+a)/(a(x-3)) . . . . . . using parentheses around the denominator
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