Question

What is the [OH-] in a solution that has a pOH = 2.28

Show explanations please.

Answer 1

The value of pOH of a solution is 2.28

We need to find the [OH-] in a solution. We know that,

pOH=-\text{log}[OH^-]pOH=−log[OH−]

Put all the values,

\begin{gathered}2.28=-\log[OH^-]\\\\=0.00524\end{gathered}2.28=−log[OH−]=0.00524

So