Question

Look at the simultaneous equations below. x 6y=10 - 3y² = 4x + 1 a) Show that 3y² - 24y - 41 = 0 b) Use part a) to solve the simultaneous equations. If any of your answers are decimals, give them to 1 d.p.​

Answer 1

To solve the simultaneous equations, we use the method of substitution. We solve one of the equations for x and substitute it into the other equation. By simplifying and combining like terms, we obtain the equation -3y² - 24y - 41 = 0.

Step-by-step explanation:

To solve the simultaneous equations, we will use the method of substitution. We will solve one of the equations for x and substitute it into the other equation. Let's solve equation 2 for x:

2) -3y² = 4x + 1

Subtract 1 from both sides:

-3y² - 1 = 4x

Divide both sides by 4:

x = (-3y² - 1)/4

Now we will substitute this value of x into equation 1:

1) x - 6y = 10

Substitute (-3y² - 1)/4 for x:

((-3y² - 1)/4) - 6y = 10

Multiply both sides by 4 to clear the fraction:

-3y² - 1 - 24y = 40

Combine like terms:

-3y² - 24y - 41 = 0

So, the equation -3y² - 24y - 41 = 0 is equivalent to the given simultaneous equations.

Answer 2

I don't know if it is true