Question

Find the dimensions of a rectangular lot whose length is 2km more than its width if the area is 24km²?

Answer 1

width = 3.46 km and length = 6.93 km

Explanation:

let the width be : X km

then the length would be: 2X km

as area is length x width

therefore:

2X x X = 24

2X² = 24

X² = 24/2

X² = 12

X =
`√(12)`

X= 3.46

the width would be 3.46 km while the length would be 2X = (93.46) = 6.93 km

Answer 2

4 km wide and 6 km long.

Explanation:

Let the width be x, then the length is x+2 km.

Area = width * length

Substituting the given values:

24 = x(x + 2)

24 = x^2 + 2x

x^2 + 2x - 24 = 0

(x + 6)(x - 4) = 0

x = -6, 4

As x must be positive, then x = 4.

So, the dimensions are 4 and 4+2

= 4, 6,