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Consider the rate law below.

R=K[(CH3)3 CBr] [H₂0]⁰
What is the overall order of the reactants in this reaction?
00
1
02
03

User Zheng
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1 Answer

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Answer: The overall order of a reaction is the sum of the exponents of the concentrations of the reactants in the rate law.

Given the rate law R = K[(CH3)3 CBr] [H₂0]⁰, we can see that the reactant [(CH3)3 CBr] has an exponent of 1 and the reactant [H₂0] has an exponent of 0. To find the overall order of the reactants, we add the exponents:

1 + 0 = 1

Therefore, the overall order of the reactants in this reaction is 1.

User Frida
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