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A chemical reaction between X and Y forms C according to the reaction below. The data for three trials to measure the

rate of this reaction are also given.
Trial
1
2
3
[X] (M)
0.01
0.01
0.02
X+Y→C
[Y] (M)
0.015
0.030
0.015
What is the rate law for this reaction?
OR=KX²M
OR=KX³M²
OR=KXM²
OR=KX²M²
Initial Rate (M/s)
7.83x10-5
BIBE
3.13x 104
1.57x10

1 Answer

2 votes

Explanation: The rate law for a chemical reaction is an equation that relates the rate of the reaction to the concentrations of the reactants. To determine the rate law for a reaction, experiments are typically conducted with different initial concentrations of the reactants and the initial rate of the reaction is measured.

From the data provided, it appears that the reaction is of the form X + Y → C. And the concentration of X and Y are varied in three trials and the corresponding Initial rate is measured.

In the first trial, [X] = 0.01 M and [Y] = 0.015 M, and the initial rate of the reaction is 7.83x10-5 M/s.

In the second trial, [X] = 0.01 M and [Y] = 0.03 M, and the initial rate of the reaction is 3.13x104 M/s.

In the third trial, [X] = 0.02 M and [Y] = 0.015 M, and the initial rate of the reaction is 1.57x10 M/s.

Given the data, the rate law for this reaction is OR = KX²M. This is because when the concentration of X is doubled, the rate of the reaction is quadrupled, which is consistent with a rate law of the form OR = k[X]^2.

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