Answer: 20.7 m/s.
Explanation: To find the speed of the car, we need to use the equation for centripetal force, which is:
Fc = m * a = m * v^2 / r
where Fc is the centripetal force, m is the mass of the car, a is the centripetal acceleration, v is the velocity of the car, and r is the radius of the turn.
We know that the coefficient of friction between the car and the road is 0.57
and it is the maximum speed, so the force of friction is equal to the centripetal force.
f = Fc = m * a = m * v^2 / r
f = μ * N = μ * m * g
so
m * v^2 / r = μ * m * g
where g is the acceleration due to gravity.
By substituting the known values into the equation, we get:
(1100 kg) * v^2 / (12 m) = (0.57) * (1100 kg) * (9.8 m/s^2)
Solving for v, we get:
v = sqrt((0.57 * 9.8 * 12 * 1100) / 1100)
v ≈ 20.7 m/s
To the nearest tenth, the speed of the car is 20.7 m/s.