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How to solve x^2 + 12x = 13 using completing the square

User Skirwan
by
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1 Answer

6 votes

Answer: x = 1, -13

Explanation:

We will solve this by completing the square, as asked in the instructions. If we do this correctly, we will end up with a perfect square that will allow us to solve more easily.

Given:

x² + 12x = 13

Set the equation equal to 0 by subtracting both sides of the equation by 13:

x² + 12x - 13 = 0

Group the first two terms:

(x² + 12x) - 13 = 0

Add and subtract
(b)/(2) ^2 to the grouped terms:

(x² + 12x + 36 - 36) - 13 = 0

Regroup the terms, move the negative out and simplify:

(x² + 12x + 36) - 49 = 0

Factor the grouped terms (6 is our perfect square here):

(x + 6)(x + 6) - 49 = 0

Add 49 to both sides of the equation and simplify the factors:

(x + 6)² = 49

Square root both sides of the equation:

x + 6 = 7 x + 6 = -7

Subtract 6 from both sides of each equation:

x = 1 x - 13

User Bagle
by
7.9k points