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A 2110 kg car moving east at 10.2 m/s collided with a 3170 kg car moving east. The cars stick together and move east as a unit after the collision at a velocity of 5.03 m/s.

A) What is the velocity of the 3170 kg car BEFORE the collision? Please show your work and use this formula: +=(+)

B) what is the decrease in kinetic energy during the collision?

User Mtmx
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1 Answer

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A) To find the velocity of the 3170 kg car before the collision, we can use the conservation of momentum principle. The principle states that the total momentum of a system remains constant if no external forces act on the system. In this case, the two cars form a closed system and no external forces are acting on them.

Given:

m1 = 2110 kg (mass of first car)

v1 = 10.2 m/s (velocity of first car)

m2 = 3170 kg (mass of second car)

v2f = 5.03 m/s (velocity of both cars after collision)

Using the conservation of momentum formula:

m1v1 + m2v2 = (m1 + m2)vf

2110 kg * 10.2 m/s + m2v2 = (2110 kg + 3170 kg) * 5.03 m/s

21632.2 + m2v2 = 5234.3 + 5.03 m/s

21632.2 = 5234.3 + m2v2

subtracting 5234.3 from both sides

16397.9 = m2v2

dividing both sides by m2

v2 = 16397.9/3170

v2 = 5.15 m/s

The velocity of the 3170 kg car before the collision is 5.15 m/s

B) To find the decrease in kinetic energy during the collision, we can use the conservation of energy principle. The principle states that the total energy of a closed system remains constant.

Given:

m1 = 2110 kg (mass of first car)

v1 = 10.2 m/s (velocity of first car)

m2 = 3170 kg (mass of second car)

v2 = 5.15 m/s (velocity of second car before collision)

vf = 5.03 m/s (velocity of both cars after collision)

Initial kinetic energy of first car = 1/2 * m1 * v1^2 = 1/2 * 2110 kg * 10.2 m/s^2 = 11096.2 J

Initial kinetic energy of second car = 1/2 * m2 * v2^2 = 1/2 * 3170 kg * 5.15 m/s^2 = 8073.36 J

Initial total kinetic energy = 11096.2 J + 8073.36 J = 19169.56 J

Final kinetic energy of both cars = 1/2 * (m1 + m2) * vf^2 = 1/2 * (2110 kg + 3170 kg) * 5.03 m/s^2 = 16100.57 J

Decrease in kinetic energy = Initial total kinetic energy - Final kinetic energy = 19169.56 J - 16100.57 J = 3068.99 J

The decrease in kinetic energy during the collision is 3068.99 J

User Sachin Garg
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