The velocity of an object dropped off a cliff can be calculated using the equation:
v = v0 + at
Given:
v0 = 0 m/s (initial velocity)
a = -9.8 m/s^2 (acceleration due to gravity)
At the end of 2 seconds:
t = 2 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 2 s = -19.6 m/s
The velocity of the object at the end of 2 seconds is -19.6 m/s, downward.
At the end of 5 seconds:
t = 5 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 5 s = -49 m/s
The velocity of the object at the end of 5 seconds is -49 m/s, downward.
At the end of 12 seconds:
t = 12 s
v = v0 + at = 0 m/s + (-9.8 m/s^2) * 12 s = -117.6 m/s
The velocity of the object at the end of 12 seconds is -117.6 m/s, downward.
It's worth mentioning that in the case of an object falling freely under the influence of gravity alone, the velocity will continue to increase