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I can’t figure out this problem please help me

I can’t figure out this problem please help me-example-1
User Broersa
by
8.3k points

2 Answers

4 votes

Answer:

95 6/7

Explanation:

The perimeter can be found by adding the length and width together and then multiplying the sum by 2.

Perimeter = 2(L + W)

Where L is the length and W is the width.

So, using the given measurements:

Perimeter = 2(33 5/7+ 14 3/14) = 94 26/14

94 26/14 -> 95 12/14 -> 95 6/7

User Aracelys
by
7.4k points
3 votes

Answer:

The perimeter is
95(6)/(7) inches.

Explanation:

The formula for the perimeter of a rectangle is


P=2L+2W

We are given the length and the width. Lets evaluate the perimeter.

First lets convert the length and width to an improper fraction.

Length:
33(5)/(7)

To write 33 as a fraction with a common denominator, multiply by
(7)/(7). Then simplify.


(33*7)/(7) +(5)/(7)


(231)/(7) +(5)/(7)


(231+5)/(7)


(236)/(7)

Width:

To write 14 as a fraction with a common denominator, multiply by
(14)/(14). Then simplify.


(14*14)/(14) +(3)/(14)


(196)/(14) +(3)/(14)


(196+3)/(14)


(199)/(14)

Lets enter the 2 fractions into the perimeter equation.


P=(2*(236)/(7) )+(2*(199)/(14) )

Simplify each term.


P=(2*236)/(7) +2*(199)/(14)


P=(472)/(7) +2*(199)/(14)

Factor 2 out of 14.


P=(472)/(7) +2*(199)/(2(7))

Cancel the common factor of 2.


P=(472)/(7) +(199)/(7)

Combine the numerators over the common denominator.


P=(472+199)/(7)


P=(671)/(7)


P=95(6)/(7)

User Marcus Kaseder
by
7.4k points