Answer:
The lake decreases by a factor of 3.038 in 10 years (to 3.038 km^2).
The lake decreases by a factor of 0.00167 each month.
Explanation:
Use the given relationship A(t)=11x(.98)^t and find the value of A for t=10 years.
A(10) = 11*(0.98)^10
A(10) = 3.621 km^2
The lake has decreased by a factor of (11km^2/3.621km^2) or 3.038.
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The lake decreases each month by (0.02/12) or 0.00167 each month.