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What is 20x^6 divided by 14x^2

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Answer:


(10)/(7)x^4

Explanation:

Exponent Rules:

There is an exponent rule which essentially states:
(x^a)/(x^b)=x^(a-b)

All this is doing is essentially cancelling out the terms, since you can think of it as:
(x^a)/(x^b)\implies \frac{x*x*x...\text{, and if you recall, multiplication and division cancel. So we cancel out "b" amount of x's, leaving us with "a - b" amount of x's. Which can also be expressed as:
x^(a-b)

We can use this logic to solve our problem:
(20x^6)/(14x^2), here we can separate this into two different fractions:
(20)/(14)*(x^6)/(x^2) and we can use basic division on the left side and our exponent rule on the right side. This gives us the following:
(10)/(7)x^(6-2)\implies (10)/(7)x^4 which is our solution!

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