Question

The cab charges in a metro city include a fixed charge plus the charges for the distance covered. Linus traveled 11 miles and paid $88. For the ride of 16 miles, he paid $108. How much would Linus have to pay to travel 6 miles?

$268.00
$128.00
$98.00
$68.00

Answer 1

Explanation:

The problem can be solved by using the information provided to set up a system of equations and then solving for the unknown variable, which in this case is the fixed charge.

Let x be the fixed charge.

We know that the total cost of the 11-mile trip is the fixed charge plus the charge for the distance covered, so we can write the equation:

x + 11y = 88 (1)

We also know that the total cost of the 16-mile trip is the fixed charge plus the charge for the distance covered, so we can write the equation:

x + 16y = 108 (2)

Where y is the cost per mile

We can solve for y by subtracting equation (1) from equation (2), so:

16y - 11y = 108 - 88

5y = 20

y = 4

Now we know that cost per mile is 4$, we can substitute it in equation (1)

x + 11(4) = 88

x = 24

Now we know the fixed charge is 24$ and cost per mile is 4$, we can calculate the fare for 6 miles

24 + 6(4) = $48

Therefore, Linus would have to pay $48 to travel 6 miles.