Question

Question 10

6.25 pts
A cannon is fired horizontally at 337 m/s off of a 80 meter tall, sheer vertical cliff. How many
seconds
will have elapsed before the cannonball strikes the ground?

Answer 1

Answer: 4 seconds are elapsed before the cannonball strikes the ground.

Explanation:

Height of tower (h) = 80m

Initital velocity in x-dir (
`u_(x)`) = 337m/s

Initial velocity in y-dir (
`u_(y)`) = 0m/s

Time of flight (T)

Gravitational acceleration (g) = 10 m/s

Using second equation of motion,

h =
`u_(y)` +
`(1)/(2)`g
`t^(2)`

80 =
`(1)/(2)`×10×
`T^(2)`

`T^(2)` = 16

T = 4s