The ball will hit the ground 54.4 meters from the base of the cliff. This can be determined using the equation for the horizontal range of a projectile, which is x = vx*t. In this case, vx is 11.5 m/s, and t is the time it takes for the ball to reach the ground. This time can be determined using the equation for the vertical range of a projectile, which is y = vyo*t + 0.5*g*t^2. In this case, vyo is 0 m/s (since the ball is thrown horizontally), g is 9.81 m/s^2, and y is 45.2 m (the height of the cliff). Solving for t gives us 3.86 seconds. Plugging this value into the equation for the horizontal range gives us x = 54.4 m.