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If f(1)=8 and f(n)=f(n-1)+3 then find the value of f(6)

User Mozak
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1 Answer

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Answer:

f(6)=23

Explanation:

f(n)=f(n-1)+3

f(1) becomes f(1-1)+3

f(1-1)+3 = 8

f(0) +3=8

f(0) = 5

=

f(2) = f(2-1)+3

f(2) = f(1)+3

f(2) = 8+3

f(2) = 11

f(3) = f(3-1)+3

f(3) = f(2) + 3

f(3) = 11+3

F(3) = 14

We can see that the sequence adds three to each prior value:

x Result

0 5

1 8

2 11

3 14

4 17

5 20

6 23

f(6) = 23

User Alexander MacLeod
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