Question

Anthony measured a line to be 16 inches long. If the actual length of the line is 15.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

Answer 1

2.56% or 2.6% (to nearest 10th of a %)

Explanation:

Percent error is determined by the expression

[(Measured - Actual)/Actual]*100%

[16" - 15.6"]/(15.6")*100% = 2.56%