Question

Suppose a parabola has an axis of symmetry at x = 8, a maximum height of 1 and also passes through the point (9, –1). Write the equation of the parabola in vertex form.

Answer 1

Below

Explanation:

Vertex at 8,1 and includes point 9,-1 <=====given

Vertex form :

y = a (x-8)^2 + 1

Plug in the point (9,-1) to find 'a'

-1 = a ( 9-8) + 1

a = -2

Parabola equation is then y = -2(x-8)^2 + 1