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How many electrons have been removed from a positively charged cube if it has a net charge of 7.5 x 10^-11 C

User Chaliasos
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1 Answer

5 votes

Answer:

Step-by-step explanation:

The net charge of an object is equal to the number of electrons removed or added multiplied by the charge of an electron (1.6 x 10^-19 C).

Given: Q = 7.5 x 10^-11 C

To find the number of electrons removed we can use the formula :

Q = n * e

where Q is the charge, n is the number of electrons, and e is the charge of an electron

n = Q/e

Therefore, n = 7.5 x 10^-11 C / 1.6 x 10^-19 C = 4.6875 x 10^8 electrons

So, 4.6875 x 10^8 electrons have been removed from a positively charged cube with a net charge of 7.5 x 10^-11 C

User Emma Tebbs
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